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Thread: The Universe

  1. #91
    Gaz
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    Quote Originally Posted by DRMARIO
    They're actually searching for the Graviton, by using the Large Hadron Collider.
    hmmm... thats going to be a tough task... hope they do it in my lifetime would be interesting to see how they go about proving it.
    Mac Expert.

  2. #92
    WiiChat Member crazyman2's Avatar
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    If they do find the graviton, alot of topics taught in physics are going to have to be revamped.


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  3. #93
    Senior Member Napalmbrain's Avatar
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    If they find the graviton it'll actually do a lot to confirm the physics we already have. It looks like it's going to be difficult to detect one though...

    Quote Originally Posted by crazyman2
    Aww crap, your right. sheesh you know your stuff. i meant h/(lambda). Derived from Einsteins e=mc^2 equation of course. haha.
    Haha, now you're even further out.
    h/(lambda) doesn't mean anything, and hc/(lambda) is not derived from E=mc^2. Here's some correct equations:

    Gravitational force: F=GMm/r^2
    Electromagnetic force: F=q(E+v><B) [where >< is a vector product]



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  4. #94
    I'm Good at Games Dorkfish's Avatar
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    Quote Originally Posted by Napalmbrain
    If they find the graviton it'll actually do a lot to confirm the physics we already have. It looks like it's going to be difficult to detect one though...



    Haha, now you're even further out.
    h/(lambda) doesn't mean anything, and hc/(lambda) is not derived from E=mc^2. Here's some correct equations:

    Gravitational force: F=GMm/r^2
    Electromagnetic force: F=q(E+v><B) [where >< is a vector product]
    Advanced scientific and mathematical equations???

    *head explodes

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  5. #95
    Senior Member Napalmbrain's Avatar
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    Quote Originally Posted by Dorkfish
    Advanced scientific and mathematical equations???

    *head explodes

    Im more of an English/History kind of guy, ya know?
    Advanced? You ain't seen nothing yet. Check out the wavefunction for a hydrogen atom:



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  6. #96
    Banned Foosoo's Avatar
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    That equation is wabbajack to me, think of something actually challenging please.

  7. #97
    I'm Good at Games Dorkfish's Avatar
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    Quote Originally Posted by Napalmbrain
    Advanced? You ain't seen nothing yet. Check out the wavefunction for a hydrogen atom:

    FFS!!! I don't even know what half of those symbols are!

    Hey, i'm a sophomore in highschool dood, you can't expect me to know any of this. I don't even know what the letters stand for in the first 2 equations.
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  8. #98
    Senior Member Napalmbrain's Avatar
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    Don't worry, I wouldn't expect you to know it. Usually when solving an equation like that you'd use a computer. In fact, that equation is really even more complicated than it appears, there are other equations you have to solve to find L and Y first.



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  9. #99
    Banned Foosoo's Avatar
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    Complicated? HA! I could explain that with my eyes closed.

  10. #100
    WiiChat Member crazyman2's Avatar
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    Quote Originally Posted by Napalmbrain
    If they find the graviton it'll actually do a lot to confirm the physics we already have. It looks like it's going to be difficult to detect one though...



    Haha, now you're even further out.
    h/(lambda) doesn't mean anything, and hc/(lambda) is not derived from E=mc^2. Here's some correct equations:

    Gravitational force: F=GMm/r^2
    Electromagnetic force: F=q(E+v><B) [where >< is a vector product]

    No way, h/(lamba) is the equation for the momentum of a photon. it could also be written as hf/c. And it is derived from einsteins E=mc^2. The only way to prove a photon has momentum is by einsteins energy/mass equivalency.

    Ok so p=mv, but photons don't have mass, but they do have energy. So we can use einsteins E=mc^2. Solve for mass: m=E/c^2. Substitute that into p=mv: p=(E/c^2)v. But the velocity of a photon is always c, so that cancels with 1 of the c's on the bottom creating : p=E/c. And, as i stated in the wrong place in an above post, E=hf. Substitute in for E: P=hf/c. And because v=(lambda)f and v=c then p=hf/(lambda)f. the f's cancel and you get p=h/(lambda)


    according to physics 30 of course =). they could easily have lied about that haha.


    Its not my fault im a fast reader

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