If they do find the graviton, alot of topics taught in physics are going to have to be revamped.
hmmm... thats going to be a tough task... hope they do it in my lifetime would be interesting to see how they go about proving it.Originally Posted by DRMARIO
Mac Expert.
If they do find the graviton, alot of topics taught in physics are going to have to be revamped.
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If they find the graviton it'll actually do a lot to confirm the physics we already have. It looks like it's going to be difficult to detect one though...
Haha, now you're even further out.Originally Posted by crazyman2
h/(lambda) doesn't mean anything, and hc/(lambda) is not derived from E=mc^2. Here's some correct equations:
Gravitational force: F=GMm/r^2
Electromagnetic force: F=q(E+v><B) [where >< is a vector product]
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Originally Posted by AndThen?
Advanced scientific and mathematical equations???Originally Posted by Napalmbrain
*head explodes
Im more of an English/History kind of guy, ya know?
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Advanced? You ain't seen nothing yet. Check out the wavefunction for a hydrogen atom:Originally Posted by Dorkfish
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Originally Posted by AndThen?
That equation is wabbajack to me, think of something actually challenging please.
FFS!!! I don't even know what half of those symbols are!Originally Posted by Napalmbrain
Hey, i'm a sophomore in highschool dood, you can't expect me to know any of this. I don't even know what the letters stand for in the first 2 equations.
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Don't worry, I wouldn't expect you to know it. Usually when solving an equation like that you'd use a computer. In fact, that equation is really even more complicated than it appears, there are other equations you have to solve to find L and Y first.
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Originally Posted by AndThen?
Complicated? HA! I could explain that with my eyes closed.
Originally Posted by Napalmbrain
No way, h/(lamba) is the equation for the momentum of a photon. it could also be written as hf/c. And it is derived from einsteins E=mc^2. The only way to prove a photon has momentum is by einsteins energy/mass equivalency.
Ok so p=mv, but photons don't have mass, but they do have energy. So we can use einsteins E=mc^2. Solve for mass: m=E/c^2. Substitute that into p=mv: p=(E/c^2)v. But the velocity of a photon is always c, so that cancels with 1 of the c's on the bottom creating : p=E/c. And, as i stated in the wrong place in an above post, E=hf. Substitute in for E: P=hf/c. And because v=(lambda)f and v=c then p=hf/(lambda)f. the f's cancel and you get p=h/(lambda)
according to physics 30 of course =). they could easily have lied about that haha.
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